The permissions sets of the caller class and its ancestors (that is, all stack frames above this one) are not included in computing the intersection set.

调用类和它的上级（即所有在它 上面的堆栈帧）的权限集都 不包括在交集计算中。

youdao

Perhaps there is some sense to this, but it strikes me as peculiar that the union of the two sets contains the float 4.0, while their intersection contains the int 4.

或许这有某种意义，但奇怪的是，这两个集的合集包含浮点数4.0，而其交集包含整数4。

youdao

The resulting set will be the intersection of the resulting sets of each spec.

结果集是每种规范的结果集的交集。

youdao

Once Morningstar spit out the three sets of funds, each was subjected to the site's "stock intersection" tool, to see where the portfolios overlap.

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