双语例句原声例句
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Implicit declaration of function increment.
函数增长的隐式说明。
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Because a template constructor is never a copy constructor, the presence of such a template does not suppress the implicit declaration of a copy constructor.
由于模板构造函数终究不是拷贝构造函数，因此这种模板的出现并不会隐藏原来隐含的拷贝构造函数之声明。
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Moreover, the implicit declaration that a midsize investment bank was systematically important puts any firm at least as big as Bear in the cross-hairs of speculators.
广告此外，这一举措隐藏的含义是，中等规模的投资银行对金融系统来说也举足轻重，这一点让任何至少与贝尔斯登同等规模的公司都成了投机者密切关注的目标。
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Implicit declaration of function increment.
函数增长的隐式说明。
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