HasValue is true if the node has a text value or false otherwise.
如果节点有文本值,hasvalue值为true;否则,值为false。
The tree is traversed to check if the node adjoins any other node in the tree with respect to the address.
在树中移动,检查此节点是否与树中的任何节点地址相邻。
If the node is collapsed at creation time, the expanded value is false, if it is expanded the value is true.
如果节点在创建时折叠,expanded值将为false,而在展开的情况下该值将为true。
You can go ahead and use that equation, or you could figure it out every time, because if you know the total number of nodes, and you know the angular node number, then you know how many nodes you're going to have left.
你们可以直接用这个方程,或者每次都自己算出来,因为如果你们知道了总的节点数,又知道角向节点数,就知道剩下的节点数是多少。
And also that we know that the zero does not count as a node, if per se I actually had managed to hit zero in drawing that, so the correct answer would be the bottom one there.
另外你们要知道零点不是节点,假设说我确实把零点画成0了,那正确的结果就是底下这个。
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