Two: check to see if this is the answer, if this is the thing I'm looking for.

是否是我们要找的元素，接着，如果不是。

麻省理工公开课 - 计算机科学及编程导论课程节选

There are two possibilities. If the answer is yes, then I'm still looking for the answer, what do I want to do? Well, I don't have to do anything other than change the counter.

这就是一个测试，有两种可能的结果，如果结果为是的话，然后我就要继续找寻目标数,我该怎么做呢？好。

麻省理工公开课 - 计算机科学及编程导论课程节选

It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.

然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于，我对这两个元素进行比较,然后返回结果就可以了，否则的话，我们就去寻找中值点，注意它是怎么实现的,首先这个指向一个列表的开头。

麻省理工公开课 - 计算机科学及编程导论课程节选

He laughed at the ploy and two days later I had my answer.

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