And in this case, we go from 8 to 4 to 2 to 1 three times and then on each iteration of this algorithm, each pass across the board I'm touching N numbers, so that means I'm doing N things, log N times.
在这个例子中,我们从8得到4,到2,再到1,是3次,在这个算法的每次迭代中,每一趟我都会操作N个数,也就是所我每次要做N步操作,一共要做,log,N,次。
So as I tried to say on the board, we can have n equals 1, 1/2 but since we can't have n equals 1/2, we actually can't have a binding energy that's anywhere in between these levels that are indicated here. And that's a really important point for something that comes out of solving the Schrodinger equation is this quantization of energy levels.
我在这要说的是,我们可以让n等于,但不能让n等于,我们不能得到在这些标出来的,能级之间的结合能,能级的量子化,是从解薛定谔方程中,得到的很重要的一点。
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