du, it's an ideal gas. So this is Cv dT and of UB course we can just integrate this straight away.

因此这是CvdT，当然我们可以,直接算出这个积分，那么△

麻省理工公开课 - 热力学与动力学课程节选

dq=0 But if it's adiabatic, then dq is equal zero, du=dw and for an adiabatic process, then du is equal to dw.

但如果它是绝热的，那么，因此对于绝热过程。

麻省理工公开课 - 热力学与动力学课程节选

but right now you're going to have to take it for granted. So, if the Joule-Thomson coefficient is equal to zero, just like we wrote, du = Cv dT du = Cv dT for an ideal gas, we're going to dH = Cp dT have dH = Cp dT for an ideal gas as well.

但是现在请你们应该把它看成理所当然的,所以，如果焦耳-汤姆逊系数等于零,就像我们写的，对于理想气体,我们也可以得到对于理想气体。

麻省理工公开课 - 热力学与动力学课程节选

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