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OK. So if I look at this code, first of all I'm calling search, it just has one call, so looks like search is constant, except I don't know what happens inside of b search. So I've got to look at b search.
首先调用一下搜索,就一步调用,看起来搜索是固定的,除非我不知道二分搜索的原理,那我们来看看二分搜索吧,所以让我们看看,第一行打印出来的内容。
If you want to call something as A + B, it means that I did A and then I did B.
如果你想某个量称为 A + B,它表示我先沿着 A 走,然后是 B
It's only got two things to do, except what it really says is, that the complexity of search 1 is the same as the complexity of b search, b search because that's the call it's doing.
它只有两件事要做,其实实际上是1,它的复杂度和b,search的复杂度是相同的,因为它调用了。
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