这种检验方法仅需参数的一致估计量，便于计算。
This test only needs consistent estimator and is easy to compute.
为了证明ols估计量是渐近有效的，我们需要(1)给出一致的估计量但证明它有更大的方差。
To prove that OLS estimators are asymptotically efficient, one needs to (1) present an estimator that is consistent but its variance is larger.
是否有可能(一个估计量)是无偏却不一致的？
Is it possible for an estimator to be unbiased but inconsistent?
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