We can also figure out the energy of this orbital here, and the energy is equal to the Rydberg constant.

我们还可以在这里计算出该轨道的能量，该能量等于里德堡常数。

youdao

So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.

我们可以发现有效的z等于n的平凡，乘以电离能除以里德堡常数,这些所有再开方，所以等于n乘以,除以RH整体的平方根。

youdao

We put all of this over the Rydberg constant, which is 2 . 1 8 times 10 to the negative 18 joules, and we want to raise this all to the 1/2.

除以里德堡常数，我们想把这些所有的再开方，所以我们最后。

麻省理工公开课 - 化学原理课程节选

So let's actually just simplify this to the other version of the Rydberg constant, since we can use that here.

除以n初始的平方，我们把它简化成,另一种形式的Rydberg常数。

麻省理工公开课 - 化学原理课程节选

So now we have that energy is equal to the negative of the Rydberg constant divided by n squared.

我们可以把能量方程大大简化,现在能量等于负的Rydberg常数除以n平方。

麻省理工公开课 - 化学原理课程节选