This causes the IntegrateInt process to change the running total to 0+1=1 and thereby write the integer 1 onto channel b.
这造成 IntegrateInt 进程把汇总值修改成 0+1=1,所以把整数 1 写入通道 b。
The IntegrateInt process also writes the integer 0 (which is, after all, the current value of the running total) onto channel b.
IntegrateInt进程也把整数0(是当前汇总的值)写入通道b。
Do you see the pattern of how the integers being written onto channel a lead to those being written onto channel b, and thereby onto channel out?
您有没有看这样的模式:写入通道a的整数造成它们也被写入通道b,因此也写到通道out ?
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