Professor PI Br 瑞典白年茂教授
So what we see is that those six pi electrons are actually going to be de-localized around all six of those atoms.
我们看到,六个π电子会,巡游在所有六个原子周围。
That's -Pi times a vector.
就等于用 -π 乘以那个矢量
So z equals 7 -- this is the cut-off where, in fact, the sigma orbital is going to be higher in energy than the pi 2 p orbitals.
所以z等于7-这是分界点,实际上,sigma轨道能量,要比π2p轨道高。
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