This only works for flags with an odd number of rows.
这种模式只适用于行数为奇数的星条旗。
The collegial panel must have an odd number of members.
合议庭的成员人数,必须是单数。
If there are an odd number of miners, then the core is empty.
如果有奇数个挖矿者,那么中心为空。
so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.
假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡
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