abstract algebra [数] 抽象代数 ; 近世代数 ; [数] 抽象代数学 ; 代数结构
Linear Algebra [数] 线性代数 ; 线形代数 ; 线性代数B ; 线性代数A
Elementary algebra 基本代数 ; 初级代数 ; 高档代数
commutative algebra 可对易代数 ; 可换代数
fundamental theorem of algebra [数] 代数基本定理 ; 代数学基本定理 ; 代数学根本定理 ; 基本定理
tensor algebra [数] 张量代数
Clifford algebra 克利福德代数 ; 几何代数 ; clifford代数
Modern Algebra 近世代数 ; 抽象代数
This paper mainly discusses the application of rough sets theory to algebra system-ring.
主要讨论粗糙集理论在代数系统--环上的应用。
参考来源 - 粗糙环的同态与同构An equivalence verification method based on polynomial symbolic algebra has been proposed.
提出了基于多项式符号代数的等价验证方法。
参考来源 - 基于多项式符号代数的数字电路形式验证方法研究·2,447,543篇论文数据,部分数据来源于NoteExpress
N-UNCOUNT Algebra is a type of mathematics in which letters are used to represent possible quantities. 代数
At twenty he translated Euler's standard work on algebra into English.
20岁时,他把尤勒的权威代数著作译成了英语。
He would allow John slyly to copy his answers to impossibly difficult algebra questions.
对于那些特别难的代数题,他允许约翰偷偷抄袭他的答案。
Yet others go into mathematical procedures, but assume that the reader is adept in using algebra.
而另外一些深入探究了数学计算过程,但只面向熟悉代数的读者。
I'll leave the algebra there, transfer it up here, q1* = q2* = a - c over 3b.
先把算式留在那好了,我在这里再抄一遍吧,q1*=q2*=/3b
All right, so that's just solving out the algebra, so we're saying what q solves, a - c over 2b - q2 over 2 = 0.
没错,只需要解出当,/2b-q2/2=0,时q2的值即可
What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.
2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b
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