So we can think about now doing bonding, and now we have four equal orbitals with one electronic each.

我们现在可以考虑成键了，现在我们有4个等价的轨道，每个上面有1个电子。

麻省理工公开课 - 化学原理课程节选

I first had a list of size 8, then 4, then 2, but then I had another problem of size 2.

首先是一个有8个元素的序列，接着变成了4个元素，接着2个元素，然后我就碰到了有2个元素的另一个问题。

哈佛公开课 - 计算机科学课程节选

I've got two states here, three states here, two here, I need four, and if I can come up with these bonds, four, by the Hund rule I'd fill them like this.

我们已经有2个状态在这里，3个在这里，2个在这里，我需要4个，如果我能想到这些键，四个，通过洪特规则，我们就能像这样排布。

麻省理工公开课 - 固态化学导论课程节选