nil ring
... 东莨菪亭 scopoletin 诣零环 nil ring 非线性规划问题 non linear programming problem ...
基于28个网页-相关网页
诣零交换环 nil commutative ring
环的诣零根 nilradical of a ring
给出满足主右理想极小条件诣零环的两个充要条件，此类环是扩张闭的。
This peper gives two necessary and sufficient conditions for a ring to be a nil MHR-ring. It is obtained that any nil MHR-ring is extension closed.
youdao
应用推荐
模块上移
模块下移
不移动