要测试带括号表达式的递归路径,请尝试以下测试。
To test the recursive path for parenthesized expressions, try the following test.
大多数特殊字符在中括号表达式内出现时都会失去它们的意义。
Most special characters lose their meaning when they occur inside a bracket expression.
iPod touch用户字符串的不同之处在于括号表达式的开头为iPod,而不是iPhone。
The iPod touch user string differs in that the beginning of the parenthesized expression is iPod, rather than iPhone.
We can start having complex expressions, you can imagine we can have things are lots of parens, and all sorts of things in it. Yes, question.
我们可以开始写复杂点的表达式了,你可以想象,我们有一个很多括号的表达式,里面有各种各样的东西,什么问题。
Scratch The syntax actually looks reminiscent to Scratch, where you have a puzzle piece reminiscent of this shape, but you have to say "if" followed by a space, followed by in parenthesis, the Boolean expression that you want to check -- more on those in a moment.
这个语法看起来使人想起,那里有一个这种形状的程序块,但是你必须说明“if“后面跟着一个空格,跟着一个括号,一个你需要核对的布尔表达式,-还有更多的。
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