现在,我得到了两个平方项减去一。
我们来试着把这个表示为某些平方项的和。
这是平方项。
And again, if we write out what all the terms are, we again have 1 s a squared plus 1 s b squared, but now what we're doing is we're actually subtracting the interference term.
同样,如果我们把所有的项都写出来,同样我们有1s平方加上1sb平方,先现在我们做的是,我们要减去干涉项。
So, essentially when we're talking about these equations up here, all we're doing is talking about the regular Rydberg formulas, but instead we could go back and re-derive the equation for any one electron atom, which would just mean that we put that z squared term in the front.
所以本质上,当我们讨论,这些问题时,我们说的是常规的,Rydberg公式,但对任何其他单电子原子,我们不用,从头再推到,而是仅仅把,z平方项放在前面。
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