只要分区数多于机器数,那么增加机器就可以使此应用程序运行得更快。
So long as there are more partitions than boxes, then adding boxes will make this application run faster.
当我们说到能量时,我们只要一个量子数。
When we talked about binding energy, we just had one quantum number.
那么,只要用户输入小于42的数,一切都正常。
Then, so long as the user types Numbers below 42, everything works.
And it turns out that simply by counting the number of those spikes that occurs at a period of time.
随后,只要数一数在一定时间内,产生的尖峰脉冲的数量。
So now we're just counting up our orbitals, an orbital is completely described by the 3 quantum numbers.
所以现在我们只要把这些轨道加起来,一个轨道是由3个量子数完全确定的。
Knowing that, I'm going to say, OK, how many pigs are there, well that's just how we're, however many I had total, minus that amount, and then I can see, how many legs does that give, and then I can check, that the number of legs that I would get for that solution, is it even equal to the number of legs I started with, ah! Interesting. A return.
它将给我返回头的总数,知道了这些之后我可以说好了,有多少猪呢,无论有多少组鸡的数目,我只要用总数减去那个值,之后我就可以知道一共有多少条腿,然后再把这个值和题目中的腿数相比较,看它是否等于一开始的腿数,啊!真有趣,有一个返回值。
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