对剩下两个 XSLT 原语重复此过程。
因为我们有一对,在2s轨道里已经配对了,所以只剩下两个电子可以用来成键。
Because we have paired set in a 2 s orbital, so all we're left essentially is two electrons that are available for bonding.
现在只剩下两个次要的任务 —— 初始化互斥锁和启动线程运行可上传的文件的列表。
This just leaves us with a couple of minor bookkeeping tasks -- initializing the mutex and starting a thread to run through the list of uploadable files.
Clearly, we put 2 for each bond, and now we end up having 2 remaining bonding electrons left.
显然,我们在每个键处放上两个电子,那么最后我们还剩下两个成键电子。
We're already using it up in this pi bond here, so that means we're limited to only two other spots on the molecule, so we have three.
我们已经把它用到这个π键里去了,所以这意味着,我们在分子里只剩下两个位置,所以一共是三个。
Lithium has three electrons. If it loses two one remains. What is this formula telling us?
锂原子有三个电子,如果它失去两个,剩下一个,那么这个式子告诉了我们什么?
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