如果巧克力松糕变量的临界值可以是 -1，那么目标函数就还可以改进 0.275，但是对于这个问题的具体情况来说，这当然没什么用处。

This marginal says that if the value of the brownie variable could ever be -1, the objective function would improve by 0.275, but of course that is not useful for this problem's setup.

youdao

也就是说，如果你可以解出来或者去除掉这些变量的点，就是临界点，当你有这样的问题要解决的时候，我们找到临界点了，它们一定是最大值点或者最小值点吗？

That means if you were able to solve and eliminate the variable that would be a critical point. When you have the same problem, as we have critical points, are they maxima or minima?

youdao

写一个标准的lock，在访问变量的前后创建临界区，要有“双重检查”。

Write a standard lock plus "double check" to create a critical section around a variable access.

youdao