映射到输出(作为布尔函数)的中间节点。
只要已经按文档顺序排序了这两个操作数,就不必为中间节点集分配内存。
So long as the operands are both already sorted into document order, this avoids the need to allocate memory for the intermediate node sets.
在一个队列系统中,消息被存放在中间节点,直到系统准备好发送他们。
In a queuing system, messages are stored at intermediate nodes until the system is ready to forward them.
You can start from one nucleus and go to the next nucleus, and there are no zero planes, no nodes, nothing.
你可以从一个核出发,看向另一个核,中间没有零平面,没有节点,什么也没有。
It's says find the mid-point and split the list in half. Copy of the back end, sorry, copy of the left side, copy of the right side.
找到列表的中间节点,然后在这里将列表分解成两半,后端的拷贝,左部分的拷贝,右部分的拷贝。
So if we square sigma 1 s star, we flip the amplitude so it's all positive now, but again we still have this node right in the middle.
如果我们平方1s星,我们把振幅翻转所以现在都是正的,但同样在中间有个节点。
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