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  • 有时,为每个新任务生成一个新线程是十分明智的。

    Sometimes it is perfectly sensible to spawn a new thread for each new task.

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  • 仅当您知道存在足够的空闲系统资源时才调整线程的数量。

    Only adjust the number of threads if you know that there are enough spare system resources.

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  • 您已经了解了如何更改进程的优先级,那么对于线程又该如何操作呢?

    Now that you know how to change the priority of processes, how do you do this with threads?

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  • 这些单元与基准时间寄存器相同,并且两个线程的PURR值的总和等于基准时间寄存器的值。

    The units are the same as the time base register and the sum of the PURR values for both threads is equal to time base register.

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  • 当一个线程在运行的时候,不管是上传还是下载,你可以查询进程状态并且给用户一个反馈(例如一个进度条)。

    While a thread is running, either uploading or downloading, you can query it to check on its status to provide the user with feedback (e.g. a progress bar).

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  • 调优适当的线程池以限制并发线程的数量。

    Tuning the appropriate thread pools to restrict the number of concurrent threads.

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  • 线程化方式简单地冻结并存储现有的线程。

    The threading approach simply freezes and stores an existing thread.

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  • 允许使用原始线程创建这两个RT线程。

    The primordial thread is allowed to create both RT threads.

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  • 将可运行线程提交到自定义线程池。

    A Runnable is submitted to a custom thread pool.

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  • 这些对象只供线程组中的线程访问。

    These objects are accessible only by threads within the group of threads.

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  • 等待这些线程完成。

    Wait for the threads to complete.

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  • 这阻塞了主线程但是在另一个线程上执行代码。

    This blocks the main thread but executes the code on another thread.

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  • POSIX线程提供了线程化机制和共享内存。

    POSIX threads provide the threading mechanism as well as Shared memory.

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  • 线程支持,含线程同步功能。

    Threading support has to be implemented including synchronization features.

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  • 第二列是线程,表明锁竞争发生哪个线程。

    The second lane is thread, indicating in which thread lock contention occurs.

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  • 什么是线程?

    What are threads?

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  • 线程汇大小。

    Thread pool size.

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  • 如果未配置轮询线程,则IDS将启动一个轮询线程。

    If poll threads are not configured, IDS will start one poll thread.

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  • 如果线程池中有可用的线程,它就会被使用。

    If the thread is available in the pool, it gets used.

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  • 内核线程和应用程序线程需要相互进行握手。

    The kernel thread and the application thread will handshake with each other.

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  • 线程1被线程2预占。

    Thread 1 is preempted by thread 2.

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进来说说原因吧 确定