• 我们再求一次导数,也就是对导数求导。

    Let's sneak in one more derivative here, which is to take the derivative of the derivative.

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  • 角加速度等于,角速度的导数。

    And angular acceleration is the derivative of angular velocity.

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  • 基本上是的,那就是方向导数。

    And that's basically, yes, that's the directional derivative.

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  • 它是收入Pq相对于数量的导数。

    It is the derivative of revenue pq with respect to quantity.

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  • 临界点是,偏导数都为零的点。

    So, critical points, remember, are the points where all the partial derivatives are zero.

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  • 但都是使用导数的逼近公式。

    But, it's the usual approximation formula using the derivative.

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  • 垂直于梯度的方向上,方向导数为零。

    The directional derivative in a direction that's perpendicular to the gradient is basically zero.

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  • 速度向量,是位置向量关于时间的导数。

    So, the velocity vector is the derivative of a position vector with respect to time.

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  • 因此,一个多变量的函数没有通常的导数。

    So, a function of several variables doesn't have the usual derivative.

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  • 对于任意两分量,混合偏导数相等。

    For every pair of components the mixed partials must be the same.

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  • 我们还学过加速度,也就是速度向量的导数。

    And, we've also learned about acceleration, which is the derivative of velocity.

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  • 那么dx和dy前面的系数就是偏导数。

    OK, and so the coefficients of dx and dy are the partials.

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  • 我们首先要做的事是,求偏导数,fx是多少?

    What we would start doing immediately is taking the partial derivatives. What is f sub x?

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  • 首先考虑第一个分量,求出它关于x的偏导数。

    Ry-Qz Well, so we have to take the first component, Ry minus Qz, and take its partial with respect to x.

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  • 这一因素被称为是“二阶导数”,或者是变化率的变化率。

    This factor has been dubbed "the second derivative", or the rate of change of the rate of change.

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  • 未知量是一个函数,这个方程,将把函数的偏导数联系起来。

    So the unknown is a function, and the equation will relate the partial derivatives of that function to each other.

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  • 基本上,答案就是,我们不可以用二次导数来验证这个情况。

    Basically, the answer for us is that we don't have a second derivative test in this situation.

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  • 扭矩除以转动惯量,就会引起角加速度,也就是角速度的导数。

    Torque divided by moment of inertia is what will cause the angular acceleration, namely the derivative of angular velocity.

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  • 这个类似于,力除以质量等于加速度,就是速度对t的导数。

    That is the analog of force divided by mass equals acceleration, which is d over dt of velocity.

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  • 这样x为自变量,z为因变量,这条曲线的斜率就是关于x的导数。

    And when I change x, z changes, and the slope of that is going to be the derivative with respect to x.

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  • 这是一个临界点,考察它的二阶导数,会发现这确实是一个极大值点。

    That is a critical point. And we used the second derivative to see that this critical point is a local maximum.

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  • 还记得吧,对一个量的平方求导,就得到这个量的2倍,乘以这个量的导数。

    Remember, we take the derivative of the square. We take twice this quantity times the derivative of what we are squaring.

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  • 人与数据库交互:他们引导数据流的走向;他们解释并处理数据请求。

    People interact with databases: they direct data flows; they interpret and service data requests.

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  • 和以前一样,它来源于这样一个事实,混合二阶导数,求导次序改变,结果不变。

    And, as before, this comes from the fact that the mixed second derivatives are the same, no matter in which order you take them.

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  • 我确信你们仍然记得一些简单的规则,并且能够迅速地告诉我x2的导数是2x。

    I'm sure you remember some of the simpler rules for differentiation and could quickly tell me that the derivative of x2 is 2x.

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  • 有必要对加速度给出一个严格的定义,加速度,作为一个矢量,是速度的一阶导数。

    So, the definition will take effect. The acceleration is as a vector, and the acceleration vector is just the derivative of a velocity vector.

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  • 他们说,二阶导数正在趋正,意思是:尽管经济仍在下滑,但是下滑的速度减缓了。

    The second derivative, they say, is turning positive. That means that although the economy is spiralling down, it is doing so more slowly.

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  • 如果取的向量场是处处恒定的,所有点都是平移关系,所以没有散度,因为导数为零。

    If you take a vector field that is a constant vector field where everything just translates then there is no divergence involved because the derivatives will be zero.

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  • 微积分基本定理,不是曲线积分的,告诉我们,如果对函数的导数积分,就会得回原函数。

    So, the fundamental theorem of calculus, not for line integrals, tells you if you integrate a derivative, then you get back the function.

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  • 微积分基本定理,不是曲线积分的,告诉我们,如果对函数的导数积分,就会得回原函数。

    So, the fundamental theorem of calculus, not for line integrals, tells you if you integrate a derivative, then you get back the function.

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