Scientific calculator supporting addition, subtraction, multiplication, division, square-root, square, cube, sin, cos, tan, Factorial, inverse, modulus.
科学计算，加、减、乘、除、开方、平方、三次方、三角函数(sincos tan)、阶乘、求反、取模等。
For example, in Listing 3, it would be good to receive an error message when doing square-root (-22.0) and exiting the program with return status -1 instead of returning -1.0.
例如，在清单3中，当执行square - root(- 22.0)时应该产生错误消息，程序退出，返回状态应该是- 1而不是- 1.0。
The principal square root function is defined using the nonpositive real axis as a branch cut.
主平方根函数是使用非正实轴作为分支切割定义的。
If you can harvest factors in pairs, you need only check factors up to the square root of the target number.
如果您成对获取因子，您只需要检查到目标数的平方根即可。
First, I take the range of numbers from 1 to the target number's square root plus 1 (to make sure I catch all the factors).
首先，获取数的范围是从1到目标数的平方根加 1（确保能取到所有因子）。
Measure a person's general ability; then measure their cleverness, then square both numbers and add them together, then take the square root.
衡量人们的总体能力，然后衡量他们的聪明度，算出两个数字的平方，再把它们相加，最后求出平方根。
Without proof-- - you will see this if you ever take 803-- I will tell you that the speed of sound is the square root of Young's modulus divided by the density of the material.
现在不证明-,你们将在803章学到-,我告诉你们声速,是杨氏模量的平方根,除以介质的密度。
For example, for the number 16, the square root is 4, which inadvertently gets added to the list twice.
例如，对于数字16，平方根是4，该数字将被意外地添加到列表中两次。
It turns out that when you harvest the Numbers in pairs, you accidentally grab Numbers twice when you reach a whole-number square root.
结果是当您成对地获得数字时，您在到达整数平方根时将意外地获得两次数字。
You also send a fault response if someone requests the square root of a negative number.
如果有人请求负数的平方根，也将发送错误响应。
It loops through all of the integers that are less than or equal to the square root of the input integer.
对输入的整数求平方根，遍历所有小于或等于平方根的整数。
You may think that the uncertainty in there equals the square root 1 of 372 plus or minus 1 1 divided by 186 plus or minus 1.
你也许认为这个误差,=372加减1的,平方根1,除以186加减。
So now we can measure these times and then we can take the ratio and then we can see that the time that it takes is proportional to the square root of the height.
我们马上来测量时间，再取其比值，接着对比，看时间是否与高度的平方根，成正比。
The code in Listing 5 first gathers the list of factors up to the square root of the target number, saving it in the factors variable.
清单5中的代码首先将该因子列表收集到目标数字的平方根，将其保存在factor变量中。
I then append a new collection onto factors - generated by the map function on the factors list - applying the code to generate the symmetrical (the matching factor above the square root) list.
然后我将一个新的集合附加至由factor列表中的map函数生成的factor上，应用此代码生成对称的(平方根上方匹配的因子)列表。
I want to then do, I need to find the square root b squared plus h squared, right?
我接下来要求b的平方和h的平方,的和的平方根对不对？
I mentioned earlier, notice that the orbital period and the escape velocity vary by a square root of two if you are at a particular position.
我之前说过，注意，轨道时间和逃逸速度，因2的平方根不同，如果你在某特定位置。
Filter all of the target number's factors from 1 to the square root of the number.
过滤目标数的所有因子，从1到其平方根。
The first line defines a function called square that takes an argument and emits its square root.
第一行定义一个名为square的函数，该函数可接受参数并发出其平方根。
The params element contains one param element that contains a double whose square root is desired.
params元素包含一个param元素，param元素包含double, double的平方根是希望得到的值。
List methods are convenient for these types of manipulations, but a side-effect of my algorithm is a duplicate entry when a whole-number square root pops up.
List方法对于这些类型操作很方便，但我的算法有个副作用，就是出现整数平方根时，会有重复。
If you want to escape from this, you will need a speed which is the square root of two times larger than that orbital velocity.
如果想要逃离这里，你将需要一个速度，是轨道速度2倍大的，平方根。
Then the intent is to take the square root; however, this works only if the display type of the field is Number as shown in figure 8.
则目的是求平方根；但是仅当字段的显示类型是Number(如图8所示)时才能工作。
But the system variance is going to be on the order of the square root of N times epsilon.
但是系统能量的变化量大约,会是N的平方根乘以ε
Can you do the math: What is one hundred times four, divided by the square root of a hundred?
你会做数学吗：100乘4除以100的平方根是多少呢？
The period, which is 2 pi times the square root of l over g, if you substitute in your length of 5.1 meters, you will find 4.57 seconds.
周期，等于2π,乘以l/g的平方根，如果把长度为5。1米,代入，会得到4。57秒。
where (with pi = 3.1415... and sqrt() denoting the square root)
其中 (pi = 3.1415...，sqrt()表示平方根)
He says if you take the square root of their risk it Narrows the gap between them - so you check Mr X only 10 times more often than Mr Y.
他表示，如果你把风险开方，检查次数就少很多，所以只要让甲乘客比乙乘客多检查10次就可以了。
Before moving on I can describe a very simple example of pre - and post-conditions: a routine that computes the square root of a real number.
在结束此话题之前，我可以举一个有关前置和后置条件的简单例子：一个例程要计算一个实数的平方根。
Before moving on I can describe a very simple example of pre - and post-conditions: a routine that computes the square root of a real number.
在结束此话题之前，我可以举一个有关前置和后置条件的简单例子：一个例程要计算一个实数的平方根。
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