• C1 be the right-most character of s1.

    C1是S1最右侧的字符。

    youdao

  • S1: How many boys?

    S 1:多少男孩?

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  • So, the address is 71 so what ends up in s1?

    地址是71,那么最终s1是什么?

    youdao

  • For example, schema_map ((s1, t1), (s2, t2)).

    例如,schema_map ((s 1,t1),(s 2,t2))。

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  • This statement is represented in the example as subquery S1.

    这个语句在示例中表示为子查询s1。

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  • If it's okay, convert the remaining chars in s1 into an integer.

    如果没有问题,则将s1中的余下字符转换成整数。

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  • In this case, the LCS of S1 and S2 is clearly a zero-length string.

    在这种情况下,S1和S2的LCS显然是长度为零的字符串。

    youdao

  • In that case, your S1 or S2 breakout stop would get you out with a profit.

    如果是那样,用系统1或系统2的突破止损能帮助你兑现利润。

    youdao

  • On S1, no specific procedure corresponds to the NAS node selection function.

    在S1接口,没有专门的过程应用于NAS节点选择功能。

    youdao

  • Then, we would have to add a NULL character after the last char copied into s1.

    然后,我们可以在复制到s1的最后一个字符后添加NULL字符。

    youdao

  • The second aggregation function is applied to the partially calculated results of S1.

    第二个聚合函数应用于S1的部分计算结果。

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  • Now the functional test script, S1, is associated with the TestManager test case, TC1.

    现在功能性测试脚本,S1,就与TestManager测试用例,TC1联系在一起。

    youdao

  • Suppose f of x, y, z equals k1, that is my equation, s1 and it gives me a solution s1.

    假设我的方程是这样,然后给出了一个解。

    youdao

  • Well, let's think about comparing the flux integral for S1 and the flux integral for S2.

    让我们考虑关于S1和S2的通量积分的比较。

    youdao

  • Then we check that the first two chars of s1 are "-s", to indicate the start page option.

    然后我们检查指示起始页选项的s1的头两个字符是否为“-s”。

    youdao

  • Since you suspended the change to S2, you have version S1 selected again in your workspace.

    由于您悬挂了到S2的变更,所以您的工作区中再次选择了版本s1。

    youdao

  • S1: I see, but I had always thought that banking started during the Renaissance in Europe.

    教1:人明白了,但人本来不断以为银止业务始于欧洲白艺复亡时期。

    youdao

  • Next, you need to obtain the actual alignment strings - S1 'and S2' - and the alignment score.

    接下来,需要得到实际的比对字符串—s1'和S2 '—以及比对的得分。

    youdao

  • Let's just assume that s1 is a pointer and as an arrow suggests it's pointing at this byte here.

    我们假设s1是一个指针,就像箭头所表示的,指向这个字节。

    youdao

  • During flexion, these forces increase and also appear in higher levels of the spine above L5-S1.

    当屈曲时,这种剪切力量增加,并同样出现在L 5 - S1较高的节段水平。

    youdao

  • In the example, this is represented by the outermost select statement, which USES S1 as a subquery.

    在这个示例中,这由最外层的选择语句表示,这个语句将S1用作子查询。

    youdao

  • So, in Listing 6, step S0 is executed followed by steps S1 through S4, which are executed simultaneously.

    所以,在清单6中,执行完步骤s0之后执行步骤s1到S4,它们是同步执行的。

    youdao

  • Select the functional test script name, S1, which you need to associate with the TC1 test case, and click OK.

    选择功能性测试脚本名,S1,您需要将其与TC1测试用例相联系,并点击OK。

    youdao

  • (the following example USES down-level client c1, V8.2 client c2 and V8.2 server s1 to illustrate the scenario).

    (下面的例子使用未升级的客户机c 1、V8.2客户机c2和V8.2服务器s1来解释该场景)。

    youdao

  • The existing DB2 system has 3 DPF partitions (S1, S2, and S3), and the new system requires only 2 partitions (T1 and T2).

    现有的DB 2系统有3个DPF分区(S1、S2和S3),而新系统只需要2个分区(T1和T2)。

    youdao

  • Last week ZDNet reported that Facebook could make its S1 filings as soon as next month citing employees at the social media company.

    而上周,ZDNet援引Facebook员工的话表示,这家社交媒体公司最早可能于12月就提交S1上市申请。

    youdao

  • Last week ZDNet reported that Facebook could make its S1 filings as soon as next month citing employees at the social media company.

    而上周,ZDNet援引Facebook员工的话表示,这家社交媒体公司最早可能于12月就提交S1上市申请。

    youdao

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