• string.space([n[,pad]]) Splits words in string with n pad characters between them "one two three".space(3) returns "one two three"

    space([n[,pad]])分隔字符串中的单词,并在单词之间填充 n个字符 "one two three".space(3)返回 "one two three"

    youdao

  • Because this result is held in an integer variable, a message to display the value should use a formatting code to pad to four characters with leading zeros for codes that are numbered less than 1000.

    由于这个结果保存整数变量中,因此,显示消息应该使用格式化代码代码填充具有前导零四个字符。该代码数量不到1000个。

    youdao

  • I use a block cipher algorithm for encryption that requires the clear data bytes to be in blocks of 8 bytes, so I pad the last incomplete block with some characters.

    需要明文数据字节放在8字节加密使用密码算法所以一些字符填充最后一个不完整的块。

    youdao

  • So I'll just pad the remaining RACES with leading zeros, giving all RACES the same number of characters.

    因此前导零填充其余比赛所有比赛赋相同数量字符

    youdao

  • So I'll just pad the remaining RACES with leading zeros, giving all RACES the same number of characters.

    因此前导零填充其余比赛所有比赛赋相同数量字符

    youdao

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