A low priority thread (at priority P3) acquires the lock on an object and is pre-empted by a higher priority thread (at priority P1), as the specification mandates.
就像规范要求的那样，一个低优先级线程(优先级p3)获取了一个对象的锁，会被一个高优先级(优先级p1)的线程夺取执行权。
P1 p2 v1 v2 and here is the final situation.
这是初始状态，p1，，p2，，V1，，V2，--，so，here，is，the，initial，situation，这是末状态。
I'm showing my age, and my history here, p1 Hey, there's a bad English sentence even worse, now I'm really thrown off.
这真的看出我的岁数大了，也看出我以前的经历来了，和p2相等么？，is，p，1，and，p，2，the，same，thing？,嘿，还有个更坏的英语句子呢,现在我真的是落伍了，我正在用Python内置的比较器。
Since P1 and P2 were already in Normal form, the combining process is simply a matter of taking an assertion from each alternative and forming new alternatives that contain all the assertions.
由于P1和P2已经是标准化格式，组合过程只是简单的从每个替代中取出断言，最后形成一个包含所有断言的新的替代。
Finding 5 of your friends on P1 will grant you access to our community.
只需在P1上找到5位您的好友，即可获得加入社区的机会。
In this categorization - P1 is the highest priority, P2 is the next highest and so on.
在这个分类中-P 1是最高优先级，P 2是第二高优先级等等。
The net effect is that P2 priority threads run in preference to the P1 thread which is not what the specification requires.
实际看到的效果是P2优先级的线程要优先于P 1线程，而这并不是规范里要求的。
The system detects that the P3 thread is holding a lock required by the P1 thread and elevates its priority to P1 until the lock is released.
如果系统检测到P 3线程正在持有一个P 1线程需要的锁，则会把P 3线程的优先级置为P1，直到它释放了锁。
The input parameter named "P1" is of data type integer, the other input parameter "P2" is of type character.
输入参数 “P1”的数据类型是整型，另一个输入参数 “P2” 的数据类型是字符型。
I recommend that you only include P1, P2 and P3 requirements in your MRDs, as lower priorities are unlikely to get done in most projects anyway.
我推荐你只要包括P 1,P 2,P3的需求在你的MRD中，在多数的项目中更低的优先级可能未必会实现。
The P1 thread then needs the same object but cannot acquire the lock until the P3 thread has released it.
P1线程需要同一个对象上的锁，但是在P3线程释放它之前，P1无法得到锁。
How can P2 and P3 reference a temporary table declared in P1 without re-declaring it themselves?
P2和P3又如何能引用P 1中声明的临时表而无需再重新声明呢？
I've found that classifying requirements into categories like P1, P2, P3... works just fine.
我发现把需求分等级就像P 1,P 2,P3…这样工作的刚刚好。
The processors pairs P1 and P2 and P3 and P4 have 2.0 processing units each.
处理器对P1和P2以及P3和P4都拥有2.0的处理单元。
The T129 P1 prototype was flown by test pilots from AgustaWestland and Turkish Aerospace Industries (TAI).
该T 129小样机的试飞员来自韦斯特兰公司和土耳其航空航天工业公司(TAI)。
A stored procedure P1 may declare a temporary table t, populate it, and wish to call procedures P2 and P3 to process the data.
存储过程P 1声明临时表t，填充它后并且希望调用过程P2和P 3来处理数据。
That's if you have a curve bounded by P0 and P1.
即如果有一条被P0和P 1界定的曲线。
You don't have to write out premise one in full you can just write P1, or you don't even have to write that, you can just assume the premises come first and then the conclusion.
你们不用把前提1全都写出来,就写P！，或者什么都不写，假设前提在前面,结论在后面。
These can be parameterized (p1, p2) and you can define the parameter variables later on, before using it in a plot command.
这些函数可以用参数(p 1,p2)表示，您可以稍后在plot命令中使用它们之前再定义参数变量。
It's nR log of p2 over p1 for the process where there's a pressure change.
结果是dS等于nR乘以p2除以p1的对数，这是对压强变化的结果。
P1 I said let's do this slowly enough that this p1 is in equilibrium with this p1, but not so slowly that this pressure is equivalent to that pressure.
我曾说过我们足够慢地使这边的1，与这边的p1平衡，但是没有慢到，这里的压强等于这里的压强。
Also notice that p3 is located below p1, which causes the submit button to appear below the caption.
同时需要注意，p 3位于p1下方，这使得提交按钮出现在标题下方。
Record the highest volume ID (second column), for instance 0513, and the Extentpool (eighth column) it belongs to; in this case, LSS 05 belongs to extentpool P1.
记录最高的卷ID（第二列），例如 0513，以及它所属的区段池 (Extentpool)——即第八列；在这个示例中，LSS05属于区段池P1。
Then a procedure p1 was created which references the temporary table.
然后创建了引用临时表的过程p1。
p I put the point in an awkward place xB Let's put it right there. p1, and composition xB.
等于p1，我再次选择，p，is，equal，to，p1。，Again，一个比较棘手的位置,放在这，p1和组分比。
You have a local UDB procedure, P1, which invokes the federated procedure and is defined as.
有一个本地udb过程P1，它调用联邦过程，其定义如下。
P1 If we have a curve c, from a point p0 to a point p1 then the line integral for work depends only on the end points and not on the actual path we chose.
如果曲线c，起点为P0，终点为1，那么计算所做功的线积分，只与端点位置有关，而与我们选择的路径无关。
So if you rearrange your equations so p1, T1 are now some reference point.
如果你重写这个方程，让p1和T1变成参考点。
So, patterns p1 through p5 have energy levels.
所以，图案p1到p5有能量级别。
So, patterns p1 through p5 have energy levels.
所以，图案p1到p5有能量级别。
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