Wagoner: "Don't get all finance-y on me — that's my specialty, not yours."
瓦格纳：“别跟我扯财务——我比你更擅长。”
Since always. It's like dating language. Y 'know, like 'It's not you' means' It is you '.
永远。这是约会用语。懂吗？就像‘不怪你’其实就是‘就怪你’。
This paper mainly focuses on the Chinese format "Not X Not y" and the corresponding issues.
本文主要讨论现代汉语“不x不y”格式及其相关问题。
Y: Sort of, there are computer models and prototypes, but it's not like you can buy one at a car dealership.
Y：算吧，已经有计算机模型和汽车原型了，但是想在车行买到可能还不太现实。
The example application is really not concerned with the accuracy of the sensors, but rather the current X, Y, and Z values of the sensors.
示例应用程序不关心传感器的准确度，但关注传感器当前的X、Y和Z值。
Y He's not returning A or B or temp, and definitely not X or Y; so he just did all of this work and yet that's it.
他不会返回A或B或temp，肯定也不是X或;,所以他刚才做了所有的工作，就是那样。
z That constant, again, does not depend on y, but it can still depend on z because we still have not said anything about partial with respect to z.
同理，这个常数不依赖y，但它仍然依赖于,因为我们还没有提到关于z的偏导。
It states whether the mining model classifies the current patient as someone who will suffer the disease (y) or not (n).
它表明挖掘模型将当前病人归为哪种类型，将患上(y)还是不会患上(n)这种病。
Just because they aren't doing X, y, or Z doesn't mean they can't do it but rather they chose not to.
他们没有做其他事，并不意味着他们做不了，而是他们选择不做。
Well, first of all, the origin is not one of them, (x, y, z) being (0, 0, 0) would not solve that equation.
好，首先，原点不是其中的点，(x,y,z)为(0,0,0)不是该方程的解。
Iters left No, it is not. Therefore, skip the rest of that block of code - and go to the next instruction, which is, y ah, print out y.
是不是大于0？，Is，iters，left’s，value，greater，than，zero？,不，这回不是了，因此，跳过这块代码,而去执行下一个指令，也就是，显示。
The transition to Xmarks adds a few semi-nifty, social-y features to your searching and bookmarking, but if you're not keen on those changes, you can easily disable them in the Xmarks preferences.
而Xmarks则添加了一些比较社会话的搜索和书签功能，如果你不喜欢这些的话，通过Xmarks设置就可以简单的禁用。
Y I'm not passing an x and I'm not passing a Y, &y I'm passing an ampersand x and ampersand y and can you take a guess as to what the ampersand operator must mean?
我不是传递X，也不是传递，我传递的是&x和,你们可以猜一猜,这个&符号是什么意思？
Many projects have great functional requirements coverage (the application should do X, it should not do Y, and so on), but they rarely have requirements for para-functional requirements.
许多项目拥有大量的功能性需求覆盖范围（如果应用让您做X，那么您就不该做Y，等等），但是他们只对辅助功能性需求拥有需求。
It's because we already know that is the right X and y, so why not take the correct combination here and see what happened.
因为我们已经知道那是恰当的x和y的值。所以，何不取正确的现成的组合，同时来看会发生什么。
Please note that trustchk -y did not give any messages in the above execution, which means that the command integrity is preserved.
请注意，trustchk - y在上述执行过程中没有给出任何消息，这意味着该命令的完整性得到了保护。
It applies to character data types and those data sources for which the COLLATING_SEQUENCE server option is not set to 'y.'
它适用于字符数据类型以及COLLATING_SEQUENCE服务器选项没有被设为“Y”的那些数据源。
But, that's not the problem. It's still a valid function of x and y.
但那不是问题，它仍然是个关于x和y的有效函数。
If x is not equal to y, then the first example prints nothing while the second prints a single line with "world" on it.
如果x不等于y，那么第一个实例什么都不打印，而第二个打印出一行“world”。
z It means that for given values of y and z z we will get a term that does not depend on x. It still depends on y and z.
它意味着，对于任意给定的y和,我们会得到一个不依赖于x的项，它仍然依赖于y和。
The patient records contain a column that indicates whether they have one of the four heart diseases (y = yes) or not (n = no).
病人的记录中有一个列表明他们是否患有四种心脏病之一，y 表示是，n 表示否。
This means that the same person node can not exist in both named graphs in the query, and so different variables (x and y) must be used to represent them.
这意味着表示同一个人的节点不能在查询的两个命名图中同时存在，所以必须用不同的变量 （x和y）来表示它们。
Run gem install -y xfsprogs if you do not have the mkfs.xfs command.
如果没有mkfs. xfs，命令运行geminstall- y xfsprogs。
The classification problem is then to find a good predictor for the class y of any sample of the same distribution (not necessarily from the training set) given only an observation [6]:338.
所谓的分类问题就是指对于相同分布的样本x（可以是训练集以外的样本），都能预知其所属的类。
The classification problem is then to find a good predictor for the class y of any sample of the same distribution (not necessarily from the training set) given only an observation [6]:338.
所谓的分类问题就是指对于相同分布的样本x（可以是训练集以外的样本），都能预知其所属的类。
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