To do this asynchronously, the net traverses the distorted pattern, and at each node, n, it asks whether n's value should be set to -1 or + 1.
如果是异步完成，网络会遍历失真的图案，在每一个节点n，它会询问n的值应该设置为-1还是+ 1。
Once we multiply it by a very large number n, it becomes very much greater than kT.
一旦我用一个很大的n与它相乘，它就会变得比kT大得多。
Once we multiply it by a very large number n, it becomes very much greater than kT.
一旦我用一个很大的n与它相乘，它就会变得比kT大得多。
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