• Addition of two signed ints results in a signed int.

    两个有符号整数相加的结果是一个有符号的整数。

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  • It doesn't return an int.

    它不返回一个int数。

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  • Means that only int values can be passed in.

    意味着我们只能传入int值作为参数。

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  • It returns an int.

    它返回一个int数。

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  • Listing 6. int parameter definition class.

    清单6 .int形参定义类。

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  • Now I'm going to have another pointer to an int.

    现在我声明另一个int型指针。

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  • They also set a global int variable called errno.

    它们还设置名为errno的全局整数变量。

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  • A UML operation op with, an int as the return type.

    一个UML操作,并且以一个int作为返回值类型。

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  • Here the type described is that of Pointers to int.

    这里得到的类型是指向int型的指针。

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  • The class intProp represents a native int data type.

    intprop类表示一个原生的int数据类型。

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  • Enter int port channel 1 — Configures port channel 1.

    输入intportchannel1——配置端口通道1。

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  • Untyped integral constants are of type (unsigned) int.

    无类型的整数常量就是(unsigned)int类型的。

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  • The next few lines introduce the int class constructor.

    后面的几行介绍int类的构造函数。

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  • This instruction doesn't invoke Color (int, int, int).

    这条指令不会调用Color (int, int, int)。

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  • Rename attribute2 to quantity and change its type to int.

    将attribute2重命名为quantity,并将其类型更改为int。

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  • The returned int might have one of the values in Table 1.

    Table1 中显示了所有可能返回的int值。

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  • Then I'm declaring a variable called n, it's of type int.

    然后我声明了一个变量n,它是int型的。

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  • SetPort (int port) : set the port for a client connection.

    setPort (intport):设置客户机连接端口。

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  • where int([arg]) is the integer portion of the value of [arg].

    其中,int([arg])是 [arg]的值的整数部分。

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  • This can cause Pointers to be assigned to int and vice-versa.

    这可能会导致指针被赋值给int类型,或者反之。

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  • Click the default string type and select int from the types list.

    单击缺省的string类型,并从类型列表中选择int。

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  • Declare numeric variables as int or long for alignment and performance.

    为了对齐和性能的需要,请将数字变量声明为int或long类型。

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  • Listing 1 USES a tuple of int, char, and float and prints the contents.

    清单1使用int、char和float的元组并打印内容。

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  • In this example, five hits were found matching the keywords "TSRM" and "int".

    在此示例中,找到匹配关键字“TSRM”和“int”的五个匹配项。

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  • In our example app the user's age can be any valid integer (byte, short, int).

    在我们的示例应用程序中,用户的年龄可以是任意有效的整数(byte、short、int)。

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  • minor: An int to describe a variant on the type of the event; defaults to -1

    minor:一个整型值,用于描述事件类型的变体;缺省值为 -1

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  • Create a UML class class1 and add an operation op with return type int to it.

    创建一个uml类class1,并且向其添加一个操作op,其返回值类型为int。

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  • Ensure that an unsigned int is used where appropriate to prevent sign extension.

    确保使用无符号整数来防止符号扩展的问题。

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  • The implicit conversion operator is defined, which converts a Point type to int.

    隐式转换操作符将Point类型转换为int。

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  • The implicit conversion operator is defined, which converts a Point type to int.

    隐式转换操作符将Point类型转换为int。

    youdao

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