Since exp(i*pi)=-1, CPhase(pi,x) will flip the sign of the |1> component.
由于exp(i*pi)=-1,CPhase(pi,x)会对 |1>分量的符号取反。
the amplitudes for base states where x is |1> are multiplied by exp(i*a)=cos(a)+i*sin(a).
x是 |1>的基态振幅乘上了exp(i*a)=cos(a)+i*sin(a)。
the amplitudes for base states where x is |1> are multiplied by exp(i*a)=cos(a)+i*sin(a).
x是 |1>的基态振幅乘上了exp(i*a)=cos(a)+i*sin(a)。
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