集群名为c1。
On c1, how do I evaluate my integral?
那么怎么在c1上计算积分？
C1 be the right-most character of s1.
C1是S1最右侧的字符。
Last, I execute C1 again along with C2.
最后，我再次执行c1和C2。
I had to know C1, which I calculated; I measured it.
我们要知道C1值，我已经测好了。
C1 pedicle screws are stiffer than C1 lateral mass screws.
颈1椎弓根固定较侧块固定更稳定。
Assume there is an index T1X on (c2, c1) columns of a table T1.
假设在表t 1的(c 2,c1)列上有一个索引t1x。
I get that the line integral on c1 — Well, a lot of stuff goes away.
得到c1上的线积分，大部分就消去了。
OK, so I proved that my two line integrals along C1 and C2 are equal.
我证出了分别沿着C1和C2的两个线积分是相等的。
The free connection pool now contains two free connections - c1 and c2.
空闲连接池现在包含两个空闲连接：c1和c2。
None were located in front of the medial one third of the C1 lateral mass.
无一例位于C1侧块内侧三分之一前方。
C2 C1 and C2, well, I observe that if I do C1 minus C2, I get a closed path.
路径C1和C2，如果我组合C1和，就得到闭合路径。
It finds c1 in the free connection pool, and checks how long ago it was created.
它在空闲连接池中找到c1，并检查它创建了多长时间。
where runstats (no distribution) would provide us the following information for C1
runstats（无分布）将提供关于 C1 的以下信息
If the temperature goes up, c1 So that's the way you can measure the value for c1.
如果温度上升，值会下降。，the,value,for, c 1,goes, down。，这就是你可以，测量c1值的方法。
The range of values between C1=4 and C1=8 is estimated to be ((8-4)/(9-2)) * 10 = 5.71
C1=4与 C1=8之间的值域被估计为 ((8-4)/(9-2)) * 10 = 5.71。
By this time, c1 has been in the free connection pool for 6 minutes, and c2 for 3 minutes.
到此时为止，c1已在空闲连接池中存在了6分钟，c2存在了3分钟。
Relationship Between Screw Trajectory of C1 Lateral Mass Screw and Internal Carotid Artery.
C1侧块螺钉通道和颈内动脉之间的关系。
In contrast, a search on -content integration + rulebased: : c1 returned about 9,000 results.
相反，搜索- contentintegration +rulebased：c1时就返回了大约9,000个结果。
Consider the simple example of two statements targeted for table T1 - CREATE table T1 (C1 INT).
考虑一个简单的例子，例子中有两个以表t 1为目标的语句——CREATETABLET1 (C1INT)。
While class C1 may be defined originally in ontology O1, it can be extended in other ontologies.
类C1本来是由本体O1定义出来的，然而，它也可以是由其他的本体扩展出来的。
Two liquids with the very same density would have... they could have very different values for C1.
两种液体要有，相同的密度。，对C1应该有不同的值。
The Web application allows two use cases: one starting from page b1 and one starting from page c1.
该Web应用程序允许两个用例：一种是从页面b1开始，一种是从页面c1 开始。
In this case, the code has actually specified all the members of cluster c1 where the EJB is residing.
在本例中，代码实际上已经指定了EJB所在的集群c1的所有成员。
(the following example USES down-level client c1, V8.2 client c2 and V8.2 server s1 to illustrate the scenario).
(下面的例子使用未升级的客户机c 1、V8.2客户机c2和V8.2服务器s1来解释该场景)。
Since the pool contains two connections, and Minimum connections is set to 1, the connection Manager closes c1.
由于池包含两个连接，并且最小连接设置为1，所以ConnectionManager将关闭c1。
What is odd is that, according to the plan, the next iteration would be C1, the first iteration of Construction.
奇怪的是，根据计划，下一次迭代是C1，构建的第一次迭代。
The pool maintenance thread checks c1 and discovers it been in the pool for longer than the value of Unused timeout.
池维护线程检查c1，发现其在池中存在的时间大于未使用超时的值。
Locking pin, prevents from accidental disconnection and can only be unlocked with a tool. 6 mechanically codings C1 - C6.
锁紧插针，为防止意外断开，只有用工具才能解锁。6个机械编码C1- C6。标准编码为C1。
As the free pool for this factory is empty, the connection Manager creates a new connection, c1, and returns it to the application.
因为此工厂的空闲池为空，所以ConnectionManager会创建新的连接c1，并将其返回给应用程序。
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