• The COLORREF value is a 32-bit value used to specify an RGB color.

    也就是说返回的就是一个32位的颜色RGB值。

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  • The result of multiplying two 32-bit values is actually a 64-bit value!

    两个32位数相乘的结果实际上是一个 64位的值!

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  • The number of leading zeros discovered is the bit value of a particular stamp.

    所找到的前导零的数目就是特定戳记的比特值。

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  • The driver sets the search lines to an N-bit value to search for in the CAM.

    所述驱动器将所述搜索线设定为用以在所述CAM中搜索的N位值。

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  • The trick in checking CPU capability is to demand a high bit value with a short expiration.

    校验CPU能力的方法是,要求在短期间内得到高比特值。

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  • The two values are concatenated, and the five-bit value is used as the byte index of the concatenated value.

    这两个值被串接在一起,5位值用作所串接的值的字节索引。

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  • In this case, a 32-bit value was shifted left, and the result of that shift was cast to a 64-bit value.

    在这种情况下,会将32位值左移,其结果是值强制转换为64位值。

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  • Normals are encoded using Stereographic projection, and depth is 16 bit value packed into two 8 bit channels.

    法线使用平射投影,深度为16位数值,并被放进两个8位通道中。

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  • HRESULT is a 32-bit value, divided into three different fields: a severity code, a facility code, and an error code.

    HRESULT为32位元值,它划分为三个不同栏位:严重性代码、设备代码和错误码。

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  • The spu_mfcdma32 function takes a 32-bit value even though the target processor (the PPE) has a native 64-bit address space.

    即使目标处理器(PPE)拥有64位的本地地址空间,spu_mfcdma32函数也会使用一个32位的值。

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  • Since you are dealing with four 32-bit values rather than one 128-bit value, you could have different results for the different values.

    由于所处理的是4个32位的值而非一个128位的值,所以针对不同的值就可能会有不同的结果。

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  • And here you can see another constraint that USES the two registers % eax and % edx to combine two 32-bit values and generate a 64-bit value.

    在下面可以看到另一个约束,它使用两个寄存器%eax和%edx将两个32位的值合并在一起,然后生成一个64位的值。

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  • For instance, if you pass a 32-bit value to a function expecting a 16-bit value, and the value is in range, the function may never notice the extra bytes.

    举例来说,如果您将一个32位的值传递给一个期望16位值的函数,而且所传递的参数值也在正确范围之内,那么这个函数就永远不会注意到多出来的字节。

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  • To combat the problem, multiplication instructions only use the least-significant 16 bits of every 32-bit value so that the result will fit in the full 32-bit register.

    为了解决这一问题,乘法指令只使用每个32位的最低有效的16 位以便结果能够放进整个 32 位寄存器内。

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  • Although registers can hold multiple values (in this case, four 32-bit values), when passing parameters to a function, each parameter value is passed in its own register.

    尽管寄存器可以存储多个值(在本例中,4个32位值),但当参数传递给函数时,每个参数值都会在其自己的寄存器内被传递。

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  • If the size of the operand is not specified in the instruction, that means either that the size doesn't matter (as in logical instructions, for instance) or that it is using a 32-bit value size.

    如果操作数的大小未在指令中指定,这就意味着操作数的大小并不十分重要(例如逻辑指令)或者它的大小为32位。

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  • Questioning the value of a college education seems a bit like questioning the value of happiness, or fun.

    质疑大学教育的价值似乎有点像质疑幸福或乐趣的价值。

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  • For each bit position, if the bit is 0, the same bit position in the destination register USES the bit from source value 1.

    对于每个位位置来说,如果该位为0,那么目标寄存器中相同位的位置就会使用源值1该位的值。

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  • This distribution of intrinsic value down to every individual bit of life is buttressed by Nietzsche's metaphysical claim that everything is essential.

    本质价值分布到生命中每一,单独的部分,由尼采所声称的,所有都是必须的形而上来支撑。

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  • Major hardware vendors have recently expanded their 64-bit offerings because of the performance, value, and scalability that 64-bit platforms can provide.

    主流的硬件供应商最近都在扩充自己的64位产品,这是因为64位平台可以提供更好的性能、价值和可伸缩性。

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  • In most situations this does not pose a problem but for the translation of an IDL unsigned integer type whose value falls inside the number range of its highest order bit there will be a mismatch.

    在多数情况下这不会发生问题,但是当一个IDL无符号整数取值正好落在最高位所限制的取值范围中时,类型转换就会发生不匹配的错误。

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  • They're like halfway between a demo and the full game, but obviously you get a little bit more value out of it than you would a demo.

    他们好像介于试玩版和完整游戏之间,但是显然你能得到比试玩版更多的游戏价值。

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  • The value for audio bit rate is 128 KB, twice as much as the default value of 64 KB.

    音频比特率的值为128KB,是默认值64 KB的两倍。

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  • Read the value of the TB register into the 64-bit variable tbr.

    将TB寄存器的值读入 64位变量tbr 中。

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  • If the bit is 1, it USES the bit from source value 2. If you imagine each register as an array of bits, selb has the following meaning.

    如果该位为1,就使用源值2该位的值。

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  • Actually, this message would likely be sent to the class that would then result in a return value of the created object, so I cheated a bit.

    事实上,该消息将可能被发送到类,然后这将导致一个已创建对象的返回值,所以与我说的有点不符。

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  • Finally, it is interesting to mention that a 64-bit nanosecond value can represent approximately 585 years of elapsed time.

    最后,值得一提的一件有趣的事情是一个64位的纳秒值可以表示大约585年的时间。

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  • Finally, it is interesting to mention that a 64-bit nanosecond value can represent approximately 585 years of elapsed time.

    最后,值得一提的一件有趣的事情是一个64位的纳秒值可以表示大约585年的时间。

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