Well, the assignment operator makes a copy of the thing on the right and puts it in the thing on the left.
赋值操作符把右边的东西，复制到左边。
The goal here is to avoid accidentally using the single-equals assignment operator instead of the double-equals comparison operator
目标在于避免意外地使用单等号赋值运算符而非双等号比较运算符
This section discusses modeling an assignment operator for a C++ class. To generate this assignment operator for a C++ class named Class1, perform these steps
这部分讨论的是为 C++类建模一个赋值操作符。
An assignment operator was not accessible in a base class and was therefore not generated for a derived class.
基类中的赋值运算符不可访问，因此无法为派生类生成赋值运算符。
When a binary operator is overloaded, the corresponding assignment operator, if any, is also implicitly overloaded.
重载二元运算符时，也会隐式重载相应的赋值运算符(如果有)。
We'll learn more about operator overloading in the next chapter, but in this chapter we cover the assignment operator.
在下一章我们将进一步学习操作符重载，本章中我们先介绍赋值操作符。
However, you can define implicit conversion operators for a type, which enable you to use the assignment operator with those types.
不过，可为类型定义隐式转换运算符，这样就可以对这些类型使用赋值运算符。
This assignment operator implicitly performs widening but not narrowing conversions if the compilation environment enforces strict semantics.
如果编译环境强制使用严格的语义，则此赋值运算符将隐式地执行扩大转换而不是收缩转换。
To manage a class with pointer members, we must define all three copy-control members: the copy constructor, assignment operator, and the destructor.
为了管理具有指针成员的类，必须定义三个复制控制成员：复制构造函数、赋值操作符和析构函数。
To resolve C2299, do not make the copy constructor or assignment operator a template function, but rather a non-template function that takes a class type.
若要解决C2299，请不要使复制构造函数或赋值运算符成为模板函数，而使其成为采用类类型的非模板函数。
To resolve C2299, do not make the copy constructor or assignment operator a template function, but rather a non-template function that takes a class type.
若要解决C2299，请不要使复制构造函数或赋值运算符成为模板函数，而使其成为采用类类型的非模板函数。
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