Now, it's kind of a cyclical argument here because how do you sort the left half of N elements?
在这儿有点循环的意思,那么如何对N个元素中的左半部分进行排序呢？
Supply an integer, n, for the third argument to return only the first n matches; or supply -1 for all matches.
给第三个参数提供整数n将只返回前 n 个匹配；或者提供-1 返回所有匹配。
Supply an integer, n, for the third argument to return only the first n matches; or supply -1 for all matches.
给第三个参数提供整数n将只返回前 n 个匹配；或者提供-1 返回所有匹配。
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