It's all undefined behavior after that.
之后都是未定义的行为。
Doing so will result in undefined behavior.
这样做将导致未定义的行为。
Multiple compound assignments in a single statement: is it Undefined Behavior or not?
多个复合作业在一个声明：未定义的行为或不呢？
In all other cases, the behavior is undefined.
其它的所有情况，其行为都是未定义的。
If a clone is not returned, the run-time behavior is undefined.
如果没有传回复制，则表示执行阶段行为尚未定义。
If a deep clone is not returned, the run-time behavior is undefined.
如果未返回深层克隆，则运行时行为将不可确定。
If a deep clone is not returned, the run-time behavior is undefined.
如果未返回深层克隆，则运行时行为将不可确定。
应用推荐