Casting from member function pointer to another type and back, strict-aliasing issue?
铸造成员函数指针到另一个类型和背部，严格的混叠问题？
Pointers have little to do with casting, other than being part of a type specifier.
指针很少跟铸造，比其他的类型说明符的部分。
Pointers have little to do with casting, other than being part of a type specifier.
指针很少跟铸造，比其他的类型说明符的部分。
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