Q comes between P and R in the English alphabet.
英语字母表中，Q在P和R之间。
You pick two huge prime numbers "p" and "q."
首先 选择两个很大的质数“p”和“q”，并对他们求积得到“n=p*q”。
Q Here is a valid argument form. If P then Q. P therefore Q.
这里有一个有效的论点形式，如果P，那么Q，P所以。
Q can you see how that all cancels each other out? P unless Q.
你们明白这些怎样互相抵消吗？，P除非。
So, if Q is false P can't be true.
如果Q是假的，P也不会是真的。
How can P and Q be true if Q isn't true.
如果Q不为真，P和Q怎么可能为真。
So I can represent it in one line and put P and Q on the same line.
我可以用一句话代表,把P和Q放在同一句话里。
Ok, if I say something is P and Q then I say is that true?
好，如果我说P和Q，那么我说那为真？
Q And we are looking for an if P then Q.
我们看的是如果P，那么。
You then make "n" and "e" public and keep "d" as secret as you possibly can and then throw away "p" and "q" (or keep them as secret as "d").
然后将“n”和“e”公开出去，而对“d”要保密，对于“p”和“q”你可以把它们扔掉，也可以像“d”一样保密起来。
If you will forgive me for a second, Q I will still use P and Q for now.
请再次原谅我，我还是会用P和。
Let's say that my vector field has components p, Q and r.
假定我的向量场。
Let's say that my vector field has components p, Q and r.
假定我的向量场。
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