• Then each person can be friends with anywhere from 0 to n-1 other people.

    那么每一个人可以有0 ~n - 1个朋友。

    youdao

  • 1-of-n responses (send multiple requests, pick one response).

    1 - of - n响应(发送多个请求,选取一个响应)。

    youdao

  • It's more work to deal with more complicated N+1 query situations.

    处理复杂的N+1查询情况需要更多的工作。

    youdao

  • This problem is the dreaded N + 1 problem.

    这就是可怕的N +1问题。

    youdao

  • So when we count, generally, again, we start from zero, we go to N minus 1.

    当我们计数时,一般的,再次强调,我们从0开始,到N-1结束。

    youdao

  • Groups are numbered from 1 to n, whereas group (0) is the complete regular expression.

    从1到n对组进行编号,而group(0)是一个完整的正则表达式。

    youdao

  • Next, the NumbersInt process would produce (n + 1).

    接下来,NumbersInt进程会产生(n + 1)。

    youdao

  • Why is this easier than print "1.. 5 \ n"?

    为什么这比print “1. .5 \n ”还简单呢?

    youdao

  • Create alternative child Workspaces 1, 2... n, (and so on) from the root Workspace.

    从根工作区那里创建替代性的子工作区1,2…n(等等)。

    youdao

  • Otherwise, n is odd. Multiply it by 3 and add 1.

    否则,如果n是奇数,则乘上3再加1;

    youdao

  • STUDENT: PROFESSOR: Oh, I'm sorry. So it's n minus l minus 1.

    学生:,教授:不好意思,这是n减去l减去1.

    youdao

  • Eager evaluation can also help with the n+1 Selects Problem.

    即时抓取还有助于解决 n+1选择问题。

    youdao

  • STRESS TEST, n. 1.

    压力测试(STRESS TEST),名词。

    youdao

  • If there are an odd number of people, n can be written as 2k+1.

    如果有奇数位选民,人数n可以写作为2k+1。

    youdao

  • Increasing sequence of organism and total N as follow: treatment 1, 2 , 4, 5, 3.

    各施肥处理有机质和全氮增加顺序均为:处理1>处理2>处理4>处理5>处理3。

    youdao

  • N+1, Here is Rogia's station: poem, photographs, travels…

    N+1,这里是骆家驿站:诗歌、摄影、旅行…

    youdao

  • N+1, Here is Rogia's station: poem, photographs, travels…

    N+1,这里是骆家驿站:诗歌、摄影、旅行…

    youdao

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