Now change the schema name to an invalid value and observe similar errors as above.
现在，把模式名改为无效的值并观察相似的错误。
The second method is insufficient because it is still possible to enter an invalid value.
只第二种方法是不够的，因为只用这种方法仍然可能输入无效的值。
The value provided was an invalid value for an identifier authority.
所提供的值是无效的标识符颁发机构的值。
The value provided was an invalid value for an identifier authority.
所提供的值是无效的标识符颁发机构的值。
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