Let's go back to considering the wavelengths of different objects. We considered a baseball, but let's also think about now an electron.

我们来重新考虑不同物体的波长,我们刚才考虑了棒球，现在来考虑一下电子。

麻省理工公开课 - 化学原理课程节选

And so with this example here, I thought I'd propose that we consider exactly how you'd go about tackling something like this.

有了这个例子，我想我们可以,考虑一下应该如何下手,解决这样的问题。

哈佛公开课 - 计算机科学课程节选

So, let's consider some people got it wrong, however, and let's see where that wrong answer might have come from, or actually, more importantly, let's see how we can all get to the correct answer.

我们来考虑一下为什么有些人做错了，然而我们来看看,这个错误的答案从何而来，或者事实上更重要的，我们来看看怎样才能都得到正确答案。

麻省理工公开课 - 化学原理课程节选

Okay,so now let's consider the following case.

好了，让我们考虑一下以下案例。

耶鲁公开课 - 死亡课程节选

So we can have our two hydrogen atoms come in here, and what we will find is - now that we have all of our orbitals filled up -- so thinking about what this angle is here, would you expect it to be less than or greater than what we saw for ammonia before?

我们在这里有两个氢原子，我们会发现,现在我们所有的轨道都填满了-,考虑一下这里的角度，你们觉得它比在氨中看到的,要大还是要小？

麻省理工公开课 - 化学原理课程节选

All right, so if we think about b h bond here, again, it's the sigma bond, and we're going to say it's a boron 2 s p 2 hybrid orbital interacting with a hydrogen 1 s orbital.

这可以告诉我们，为什么它倾向于周围只有6个电子，好了，考虑一下这里的BH键,同样的，它是sigma键,我们说。

麻省理工公开课 - 化学原理课程节选

All right, so one thing that I want to point out, which I said many, many times on Friday, and this is perhaps the last time I'll say it, but one last time is we can think about why we only see a line for the 2 p orbital, versus we don't see separate lines for a 2 p x, a 2 p y, and a 2 p z.

好的，我还要指出一个问题，这个问题我在上周五已经说了很多很多次了，这可能是我最后一次提到它，但是这最后一次让我们来考虑一下,为什么我们只看到了一条，对应于，2，p，轨道的线,而不是分别对应于，2，p，x，2，p，y，2，p，z，的线？

麻省理工公开课 - 化学原理课程节选