• Or a subset with the maximum value, there may be more than one, and you're done.

    或者是有最大值的子问题集,可能不只一个子问题符合条件,然后就解决问题了。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And that may generalize again and it keeps going until you either get back to Adam and Eve, I guess. I don't think they were born in the US as far as I know, or you find somebody who satisfies that definition or you find that none of your parents actually are in that category.

    降低到我的父亲或者母亲,是不是天生的美国公民呢,这个问题可以继续向下分解,你甚至可以追溯到亚当和夏娃的时候,据我所知它们并不是出生在美国的,或者你要么找到一个符合定义的人,要么发现你的父母都不满足条件

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Taking the problem, recognizing that you know what, 8 even though this is a pretty big problem size 8 in this case and last time it was size 8 or in the case of the papers in size of a thousand roughly with the phonebook, I assume these are in a perfectly straight line they won't quite fit.

    以这个问题为例,你们要认识到,在这种情况下,这是个比较大的问题,其大小是,上次它的大小也是8,但在纸片那个问题中,电话簿的规模大概是上千的,现在假设这些,杯子完全在同一条直线上,虽然并不十分符合这个条件

    哈佛公开课 - 计算机科学课程节选

  • Computing square root. I'm going to capture it in a piece of code, I'm going to be able to refer to it by a name, and I'm going to suppress the details, meaning inside of that computation, you don't need to know what it does. You just need to know, if I give it the right kind of input, it'll give me back an input that satisfies the contract that I set up.

    比如计算平方根,我会用一段代码来说明,我将给它命名,并且忽略细节,意思就是在这一段计算过程中,你不用知道它做了什么,你只需知道,如果我进行了正确的输入,它将会给我符合条件的输出。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And so the value of with i will be the value of i plus whatever I can get using the remaining items and decrementing the weight by the weight of i.

    所以装上i之后的总价值,就是i的价值加上剩下物品中,符合条件者的所有价值,再在剩余重量中减去i的重量。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • If it isn't, then I'm going to go back around the loop, and notice what happens. If I get all the way around the loop, that is, all the way through that FOR loop and I never find a path that takes me through here, then the last thing I'm going to do is return a pair or a tuple with a special simple number none twice.

    如果没有,我会回到循环看看发生了什么,如果我运行了整个循环,也就是整个for循环,我仍没有找到符合条件的路径,那么我最后做的事情就是返回一对,或者一个数组的两次none值。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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