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So we're going to feel a higher z effective in the case of the ion compared to the neutral atom.
因此，我们在离子中,会比在中性原子中感受到更高的有效核电量。
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So what we're going to see is less shielding, which means that it will actually feel a higher z effective.
那么我们将会看到更少的屏蔽，这意味着将会感受到更大的有效核电量。
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We want to have that definition clear because in fact we're going to, we might want tabulate heats of reaction, right, and of course want to know what the conditions are for the tabulated values apply. And we're going to want to calculate them from other quantities and again, we're going to need to know each case what are the relevant conditions?
我们想要明确这个定义,因为实际上我们会想把,反应热制成表格，当然我们会,想知道表中的数据在什么样的,条件下是有效的，我们会,想要从其他的量中算出它们,再一次，我们需要知道,每种情形下相关的条件是什么？
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So why don't you go ahead and identify the correct electron configuration for carbon, 6 and I'll tell you that z is equal to 6 here.
所以你们为什么不开始,而且识别碳的正确的在你们做作业方面,电子构型，我会告诉你有效电荷量是。
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So let's do this considering, for example, what it would look like if we were to write out the electron configuration for oxygen where z is going to be equal to 8.
我们来做这个考虑，举例来说,如果我们写出,有效电荷量为8的氧的电子构型。
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But what's important is not where that most probable radius is when we're talking about the z effective it feels, what's more important is how close the electron actually can get the nucleus.
但重要的不是,最可能半径,当我们谈论它感到的有效电荷量的时候，更重要的是,电子实际上。
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If we have a higher z effective, it's pulled in tighter, we have to put in more energy in order to eject an electron, so it turns out that that's why case 2 is actually the lowest energy that we need to put in.
而如果有效核电量更高，原子核的束缚也就更紧，我们不得不输入更多的能量来打出一个电子，这就是第二种情况,所需要输入的,能量更少的原因。
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You just need to remember what's happening to z effective, which really tells us what's happening with all the trends, and once you know z effective, you can figure out, for example, what direction the atomic radius should be going into.
你只需要记住有效核电量的规律，实际上它会告诉我们所有的规律，只要你知道了有效核电量的规律，你就可以判断，比如，原子半径会向着哪个方向发展。
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The z effective is lower, so we have to put less energy in to get an ion out.
它的有效核电量更低，所以我们只需要更少的能量就能打出一个离子。
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Of course, if we saw no shielding at all what we would end up with 3 is a z effective of 3.
当然如果我们说没有任何屏蔽,我们最后得到的,有效电荷量是。
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So our minimum that we're going to see is that the smallest we can have for a z effective 1 is going to be equal to 1.
所以我们能够看到的,最小的有效电荷量,等于。
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And we know as we go across a row in the periodic table, what's happening is that z effective or the effective pull on the nucleus is increasing.
而我们知道沿着周期表的某一行向右看，有效核电量,或者说原子核的有效引力是在逐渐增大的。
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So again, when we check these, what we want to see is that our z effective falls in between the two extreme cases that we could envision for shielding.
所以当我们再一次检查这些时，我们想看到的是,有效电荷量处于两种极端案例中,这两种极端案例。
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So we should be able to calculate a z effective for any atom that we want to talk about, as long as we know what that ionization energy is.
我们应该可以计算出任何一个,我们想要谈论的原子的有效电荷量，只要我们知道电离能是多少。
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They're less shielded because they're closer to the nucleus, they feel a greater z effective.
它们受到少的屏蔽,因为它们离原子核更近，它们感觉到一个更大的有效电荷量。
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So it looks like not too many more than half of you got this correct, so make sure you can look at your periodic table and figure out how to think about ionization energy in terms of z effective, not just in terms of memorizing what that trend is.
看起来只有一半多一点的人,做对了，所以请大家务必做到能够通过观察周期表,并在考虑电离能时,从有效核电量的观点出发，而不是仅仅依靠记住这个规律。
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This is because even though z, the atomic number is still increasing, we are also getting further away from the nucleus.
从有效核电量方面来想一想为什么，这是因为，尽管，Z，原子序数依然在变大，但我们同时也在离原子核越来越远。
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So any of the answers that said a z effective of .
所以任何一个说有效电荷量为。
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But what you should be able to do is take a look at a list of answers for what we're saying z effective might be, and determining which ones are possible versus which ones are not possible.
但是你们应该能够做到的,是看一下这个可能的,有效电荷量的答案列表，并且确定哪些是可能的,哪些是不可能的。
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Not only are we taking away an electron here, but we're also going to decrease shielding, so the electrons that are already in there are going to feel a higher z effective and will be pulling and the atom will be getting smaller.
这不只是因为我们拿走了一个电子，还因为我们这样做会减小屏蔽效应，这样留下的电子,将会感受到更大的有效核电量,也就会感受到更强的吸引力，使得原子变得更小。
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The first is this the z effective, or how much charge is actually in the nucleus that's felt, Z or the I guess we would say the z, how much the charge is on the nucleus that holds it close together.
第一个是有效核电量，或者说实际感受到的核电荷量，又或者我想我可以说就是，使它们保持在一起的,原子核的电荷量。
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So the most basic answer that doesn't explain why is just to say well, the s orbital is lower in energy than the p orbital, but we now have a more complete answer, so we can actually describe why that is.
所以最基本的答案是那没有解释,所以我们事实上可以描述，为什么是那样，但是我们现在有一个更复杂的答案，又是有效电荷量。
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The reason it's aluminum is because aluminum has a lower z effective, so it's not being pulled in as tightly by the nucleus, and if it's not being pulled in as tightly, you're going to have to put in less energy in order to ionize it, so that's why it's actually going to have the smaller ionization energy.
原因是,铝的有效核电量更少，所以没有被原子核束缚得更紧，而如果没有被束缚得更紧，你为了电离它所需要注入的能量也就更少，这就是,它的电离能会更低的原因。
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So, why don't you take a look at this and tell me which are possible for a 2 s electron in a lithium atom where z 3 is going to be equal to three?
你们为什么不看一下这个然后告诉我对,于一个锂原子中的2s电子哪些是可能,的？它的有效电荷量,可能等于？
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And the point that I also want to make is the way that they differ, z effective actually differs from the total charge in the nucleus due to an idea called shielding.
我也想指出的一点是它们不同的方式,有效的z事实上不同于原子核的，总电荷量,因为屏蔽效应。
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And what we're actually talking about again is the zeffective. So that z effective felt by the 2 p is going to be less than the z effective felt by the 2 s.
我们实际上所谈论的,所以被2p感觉到的,的有效电荷量,有效电荷量小于2s感觉到。
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We know that it has to be equal to less than 2, because even if we had absolutely no shielding at 2 all, the highest z effective we could have is 2, so it makes perfect sense that we have a z effective that falls somewhere in the middle of those two.
我们知道它必须小于，因为即使完全没有一点屏蔽,最高的有效的z是，所以我们得到的有效电荷量处于,两者之间就非常讲得通了,让我们来看看另一个例子。
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So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
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And it turns out that if we have a, for example, for s, a very large z effective or larger z effective than for 2 p, and we plug in a large value here in the numerator, that means we're going to end up with a very large negative number.
结果是如果我们有一个，举例来说对于s一个很大的有效电荷量或者,比2p大的有效电荷量，并且我们将一个较大的值代入计算器，那意味着我们最后会得到,一个非常大的负数。
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