If de Broglie is correct, let's irradiate the nickel crystal with a beam of electrons where the wavelength of the beam of electrons is identical to the wavelength of the x-rays that were used and see what we get.

如果德·布罗意是正确的，那么镍晶体放出,电子光束,电子束的波长,和原来讲过的X光的波长是相等的,再看看得到了什么。

麻省理工公开课 - 固态化学导论课程节选