I would never wish to duplicate that, however, I think there's a take-away.

我不会再来一次，但是，我想人们应该从中得到些什么。

普林斯顿公开课 - 人性课程节选

If these are my payoffs I should go ahead and choose Alpha because that way I end up getting 3.

如果我关心我成绩我应该直接选α,因为那样我能得到3单位效用

耶鲁公开课 - 博弈论课程节选

I think it needs to be more important, not problematized, not post-911.

我觉得这个问题应该得到重视，并不是要将其妖魔化，或者恐怖化，像911事件后那样。

普林斯顿公开课 - 人性课程节选

I'm going to go there initially, so I can move this over here, so I can get the base part of that over there, I want to put that one there before I put this over here, finally I get to the point where I can move the bottom one over now I've got to be really careful to make sure that I don't cover up the bottom one in the wrong way before I get to the stage where I wish they were posts and there you go.

我要先把其他的放到多余的柱子上，然后把最底下的放到目标柱子上，我要在把除了最底下的圆盘，其他的圆盘挪过来之前,把最下面的圆盘放在这儿,因此我得出了最下面的盘子,应该如何摆放的结论,当我没得到其他盘子的正确摆放位置的时候,要很小心的确认没把错误的盘子,放在最下面的盘子上面。

麻省理工公开课 - 计算机科学及编程导论课程节选

At any rate, I don't know for certainty that I'm a harder grader, but I believe that it's the case based on reactions I get when I give the speech that I'm about to give.

不管怎么，虽然不是特确定我评分严格，但相信应该就是这样,根据我每次说这些话时得到的反应来说。

耶鲁公开课 - 死亡课程节选

I expect that if I add -A to A, I should get the guy who plays the role of 0 in this world, which is the vector of no length.

我希望如果用 -A 加上 A,应该得到一个零矢量,也就是一个没有模长的矢量

耶鲁公开课 - 基础物理课程节选

I need to divide it by three to get the average.

我应该先除3得到平均数

耶鲁公开课 - 博弈论课程节选

And once I know that she's going to choose Alpha, it's clear that I should choose Alpha and get 0 rather than Beta and get -3. So I should choose Alpha also.

一旦我意识到她会选α的时候,很显然我应该也选α来得到0单位效用,而不是选β只得到-3,所以我也选α

耶鲁公开课 - 博弈论课程节选

That in many cases, I can gain efficiency if I'm willing to give up space. Having said that though, there may still be a problem, or there ought to be a problem that may be bugging you slightly, which is how do I guarantee that my hash function takes any input into exactly one spot in the storage space?

普遍存在的增益和权衡,在许多的例子中,可以通过牺牲空间而得到效率方面的增加,话说回来，仍然存在一个问题,或者应该会有一个问题困扰着你,就是我如何保证我的哈希函数能够准确将,任一输入映射到相应的唯一的存贮空间中去？

麻省理工公开课 - 计算机科学及编程导论课程节选

That means, when I take two derivatives, I want to get a, then you should know enough calculus to know it has to be something like at^, and half comes from taking two derivatives.

也就是说,当我想求二阶导时,得到了a,你应该有足够的微积分知识,才能知道必须有类似at^的项,而这个1/2则是因为求了两次导数

耶鲁公开课 - 基础物理课程节选

Conversely, if you get an answer and it doesn't seem to make sense, then you've got to go back and ask, am I violating some of the assumptions, and here you will find the assumption that the particle had that acceleration a is true as long it's freely falling under gravity but not when you hit the ground.

反过来说,如果你得到一个结果,发现似乎是错的,那么你就应该回过头来问问自己,我是不是违反某些前提了,这个模型中,你就发现,只要质点在重力作用下自由下落,质点具有加速度a的前提是正确的,但是落地后就不成立了

耶鲁公开课 - 基础物理课程节选

Now, I hope you guys know that much calculus, that when you take a derivative of a function of a function, namely v square over 2 is a function of v, and v itself is a function of t, then the rule for taking the derivative is first take the v derivative of this object, then take the d by dt of t, which is this one.

我希望你们了解更多的微积分知识,当你对复合函数求导时,也就是说v^/2是关于v的函数,而v本身是关于t的函数,求导的法则应该是,第一步是这一部分对v求导,然后v再对t求导,得到这一部分

耶鲁公开课 - 基础物理课程节选