So, the total work that we can get out must be zero, out of the whole sum of them.

因此，我们可以从这两个热机,得到的总功，一定是零。

麻省理工公开课 - 热力学与动力学课程节选

W1 So I have my initial state, my final state, W1 my initial state, my final state here.

再加热，做功，对系统做的总功是。

麻省理工公开课 - 热力学与动力学课程节选

Delta v is positive in this direction here, the work is negative. So work on the system is positive. Work done by the system is negative.

功是负的，总而言之,外界对系统做功的符号为正。

麻省理工公开课 - 热力学与动力学课程节选

W2 If I go backwards, to work p1 becomes the negative from what I had p2 calculated before, so this becomes minus what I calculated before for w2.

应该是,总功等于,减去,等于。

麻省理工公开课 - 热力学与动力学课程节选