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I'm gonna say the same thing about the situation in the United States as I conclude my book talking about any situation in any religious tradition.
对此，我想用我新书中对于,任何宗教可能面临的任何一种情况,的总结，作为回答。
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So we can do this for any final charge we have, if we have a molecule that has a charge of plus 2, then all of the formal charges should add up to plus 2 and so on.
对于任意净电荷的情况,我们都可以这样做，比如假设我们有一个带两个正电荷的分子，那么所有的形式电荷加起来应该等于正二，等等。
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Again the claim--the explanation for why this is so is something which we'll get to in another class.
对于为何会出现这种情况的解释,我们以后的堂课上再讲。
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But for the van der Waal's gas, now it's going to be different.
但是对于范德瓦尔斯气体，情况就不一样了。
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To me that seems an accurate description of the human condition that is meaningful, not only for the Greeks and their heirs in the West, but for all human beings.
在我看来,这些对于人类情况的描述是,准确而意味深长的,不仅对希腊人和西方人,而是全人类
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And, one other thing that I failed to point out, if you take a look at the energies associated with the outermost electrons, in this case, lithium, you see it's 0.5 megajoules per mole, and then what's the 6.26?
还有另外一点我忘记提到的是，如果你观察离最外层,的电子的能量，在这种情况，对于锂，你可以得到，它是每摩尔0。5兆焦，那么6。26是什么呢？
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All right, you ready to do five?
好，对于五个盘子的情况？
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So if on each iteration of merging I'm doing eight things or more generally, N. That then begs the question, how many levels of this tree are there actually?
可见对于合并我需要迭代8次,一般情况下是N，这取决于具体问题，那么在这棵树中一共有多少层呢？
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For the simplest context in which one can motivate a vector and also motivate the rules for dealing with vectors, is when you look at real space, the coordinates x and y.
对于最简单的情况,我们能用矢量,以及相关的规则来处理的,是实空间,x-y 坐标系
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In any case, the question of value and valuation is an important one in Comus, and it's important in part because the rhetoric of the mask is saturated in the economic, the commercial, and the financial imagery that we were looking at in the last lecture.
在任何情况下，价值和评价对于Comus来说很重要，这个很重要有部分原因是,面具里的语言充满了经济的，商业的，和金融比喻的，这都是上次课我们想要寻找的。
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So strategy ?i is a best response to the strategy S-i of the other players if my payoff from choosing ?i against S-i, is weakly bigger than that from choosing Si' against S- i, and this better hold for all possible other strategies I could choose.
策略?i是其他参与人策略S-i的,最佳对策,如果此时我选?i的收益,弱优于此情况下选Si'的收益,这对于所有我可以选择的策略都成立
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And in this case we have three choices here in terms of what's going to be in the middle, so we need to decide that first.
而这种情况下对于哪个原子,在中间我们有三种选择，这是我们首先要确定的。
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So, these are two different definitions of how to think about atomic radius, but really what you find when these are measured is they come up with almost the identical values, so there are tables, you can look up of atomic radii and see these values, and you can trust them that, they work for both this definition and for this definition here, in most cases.
这就是,关于原子半径的两种不同的定义，但实际上你会发现按照这两种方法,测量出的值是相等的，因此有很多关于原子半径的表格，你可以通过查阅它找到这些值，你可以相信这些值，它们对于这两种定义都是适用的，在大多数情况下。
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And we call that, for this case, our sigma 2 s orbital.
对于这种情况，我们可以叫它sigma2s轨道。
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Right now we told you Joule did all these experiments and he found out that for an ideal gas, that the limit in and ideal gas 0 case was that the eta J was equal to zero.
现在我告诉你们焦耳,做了所有这些实验,他发现对于理想气体,在极限情况下理想气体的ηJ等于。
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- And we can think about why -- essentially we have fluorine and now we're adding another electron. So you can picture that fluorine is going to get larger in this case And that would be true for all of the negatively charged ions.
我们可以想一想这是为什么-,本质上来讲我们现在给氟原子加上了,另外一个电子,因此大家可以想象在这种情况下氟将变大,而且这对于其它负离子也是成立的。
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So, that's for Matsuzaka, and even if you don't memorize all the wavelengths for all the pitchers.
所以，那是对于松阪的情况，即使你没有记住,所有的投手投出球的波长。
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N 2 So any chemist should be able to just look at n 2 and know that it's a triple bond, but that's not something that we've learned how did to do yet, so let's go ahead and start a new topic that's going to allow us to have some sort of sense of what the valence electron configuration, which includes whether something's a single or double or a triple bond can be figured out for any given molecule.
任何一个化学家都应该能够仅仅通过看到2,就知道它有一个三键,但是我们还没学习如何做到这点，因此下面我们就开始进入一个新的主题,它将使我们能够有一定的认识,对于价电子的排布情况，包括可以对任何一个给定分子中的键是单键双键,还是三键作出判断。
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