So that means we're going to need to figure out what is the energy per photon that's emitted by that UV light.

所以那意味着我们将需要,计算出从紫外光源发射出的,每个光子的能量。

麻省理工公开课 - 化学原理课程节选

So this means that we can go directly from the energy between two levels to the frequency of the photon that's emitted when you go between those levels.

这意味着我们可以直接,从两个能级的能量得到它们之间,跃迁发射出光子的频率。

麻省理工公开课 - 化学原理课程节选

So we can figure out the energy of each photon emitted by our UV lamp by saying e is equal to h c over wavelength.

所以我们可以计算出,每个从紫外光源射出的光子,也就是e等于h乘以c除以波长。

麻省理工公开课 - 化学原理课程节选

And I use the term photon here, and that's because he also concluded that light must be made up of these energy packets, and each packet has that h, that Planck's constant's worth of energy in it, so that's why you have to multiply Planck's constant times the frequency.

我这里用光子这个词,是因为他还总结出光,必须由这些能量包组成，每个能量,包有这个h，普朗克常数代表,里面的能量，所以这就是为什么你们,要用普朗克常数乘以频率。

麻省理工公开课 - 化学原理课程节选