what we would expect to see for the energy.

我们将这些值代入来看看。

麻省理工公开课 - 化学原理课程节选

Then for any time t, you plug in the time t and you will get the location.

那么在任何时刻 t,当你代入 t 的值,就可以确定位移

耶鲁公开课 - 基础物理课程节选

So, let's say we start off at the distance being ten angstroms. We can plug that into this differential equation that we'll have and solve it and what we find out is that r actually goes to zero at a time that's equal to 10 to the negative 10 seconds.

也就大约是这么多,所以我们取初始值10埃,我们把它代入到,这个微分方程解它,可以发现，r在10的,负10次方秒内就衰减到零了。

麻省理工公开课 - 化学原理课程节选

And it turns out that if we have a, for example, for s, a very large z effective or larger z effective than for 2 p, and we plug in a large value here in the numerator, that means we're going to end up with a very large negative number.

结果是如果我们有一个，举例来说对于s一个很大的有效电荷量或者,比2p大的有效电荷量，并且我们将一个较大的值代入计算器，那意味着我们最后会得到,一个非常大的负数。

麻省理工公开课 - 化学原理课程节选