• Looking down 10 stories over Ground Zero, Marine Corporal Jonathan Rist said he hoped the new construction going on below would not remove every last shred of the buildings destroyed in the terrorist attacks of September 11,2001.

    VOA: standard.2009.08.01

  • Yale University is a non-profit corporation; the price of a share in Yale University is undefined-- it's zero over zero.

    耶鲁大学可以看作是个非盈利组织,它的股价无法定义,是零除以零

    耶鲁公开课 - 金融市场课程节选

  • Actually, you can't say what the share price is because there are zero shares and they have a zero price, so the value of the price per share is zero over zero and you can't define it.

    实际上你并不能确定它的股价多少,因为股数为零,其市值也为零,所以每股价值就是,零除以零,无法计算

    耶鲁公开课 - 金融市场课程节选

  • And a bit, B-I-T, just a shorthand for binary digit, 2 so a digit of zero over a one, bi means two, you only have two digits.

    比特,B-I-T,是binary,digit的简写,从0到1的数字,而bi表示,所以你就只有两个数字。

    哈佛公开课 - 计算机科学课程节选

  • Obviously, if the balance of pleasure over pain is positive, that's better than zero.

    显然如果快乐减痛苦是正的,即比零大。

    耶鲁公开课 - 死亡课程节选

  • q1*q2/ That's simply q1, q2 over 4 pi epsilon zero R.

    那只是简单的。

    麻省理工公开课 - 固态化学导论课程节选

  • Going around in a cycle the integral of dq over T is less than or equal to zero.

    对一个循环过程作dq除以T的积分,小于等于零。

    麻省理工公开课 - 热力学与动力学课程节选

  • t the new deal, s over , by the unemployment is down to close to zero by the middle of the War.

    如果不是新政,If,it,wasn’,萧条结束,it’,失业率也降低到接近零点,在二战中的时候。

    斯坦福公开课 - 经济学课程节选

  • du/dV So now our du/dV, dp/dT at constant T is just T times dp/dT which is just p over T minus p, it's zero.

    现在我们的恒定温度下的,等于T乘以dp/dT,在这里,等于p除以T,最后再减去p,结果是0。

    麻省理工公开课 - 热力学与动力学课程节选

  • So that's it; it's over; we've just hit zero.

    所以,它结束了;我们已经达到零点了。

    耶鲁公开课 - 金融市场课程节选

  • e The charge on the anion times minus e, so there is the minus e squared, 0R0 and divided by 4 pi epsilon zero r naught, because now I am evaluating this function at r naught, one minus one over n where n is the Born exponent.

    阴离子的电荷乘以,因此会有-e的频繁,除以4πε,因为现在我用r圈评估这个函数,1-1/n,n是波恩指数。

    麻省理工公开课 - 固态化学导论课程节选

  • I know the energy in this first pair would equal -e^2 That is just going to equal minus e squared over 4 pi epsilon zero r naught.

    我们明白第一对的能量将会等于,等于,/4πε0,R圈。

    麻省理工公开课 - 固态化学导论课程节选

  • Right. N is over here for counting from zero.

    对的,从0开始计数,N到了这边。

    哈佛公开课 - 计算机科学课程节选

  • And now the force, in its most general term / is q1q2 over 4 pi epsilon zero, which is the conversion factor r squared.

    库仑力的最基本形式,就是,其中r是一个变量。

    麻省理工公开课 - 固态化学导论课程节选

  • And we wrote something that looks, the energy is equal to minus the Madelung constant times Avogadro's number, 0R0 q1 q2 over 4 pi epsilon zero R zero.

    我们写下了,晶格能等于负的马德隆常数,乘以阿伏伽德罗常数,乘以q1q2除以4πε

    麻省理工公开课 - 固态化学导论课程节选

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